Difference between revisions of "Transitions within words"

Latest revision as of 15:56, 17 August 2009

The following table is a raw count of transitions (from 1984 by George Orwell) within a single word. ie. in the phrase "hi there" the pairs counted are 'HI' 'TH' 'HE' 'ER' 'RE' ('IT' is NOT counted as it is not within a single word).

A transition from 'O' to 'D' is counted in row 'O' and column 'D'.

To find the probability of transition to letter 'D' given letter 'T' (ie. the pair 'TD' within a single word) we would find the value in row 'T' column 'D' (2 in this case) and divide it by the sum of the elements in the row 'T' (1405 + 12 + 147 + etcetera)

However, to find the probability of a certain pair appearing in the text (as opposed to any other pair possibility) then we (once again) find the value in row 'T' column 'D' (for the pair 'TD') and then divide by the sum total of all of the elements in the table (not just in the same row as above).

	A	B	C	D	E	F	G	H	I	J	K	L	M	N	O	P	Q	R	S	T	U	V	W	X	Y	Z
A	10	898	1516	2186	17	224	837	21	1538	11	551	3120	741	6006	9	867	3	3654	4416	4633	311	700	271	20	927	53
B	463	97	0	3	2606	0	0	0	288	53	0	1051	12	1	831	0	0	635	95	33	850	26	0	0	471	0
C	1349	0	190	2	2091	0	0	1733	554	0	728	381	0	0	2260	0	6	615	22	995	364	0	0	0	60	0
D	470	7	5	226	2115	13	76	17	1366	14	0	212	23	62	990	1	0	321	596	17	250	25	13	0	256	0
E	2881	66	1219	4903	2134	504	219	111	556	5	80	1955	1434	5171	221	532	77	7575	3640	1522	104	1341	529	626	896	18
F	672	3	3	0	889	463	0	0	769	0	0	298	0	1	1438	0	0	726	19	295	331	0	0	0	25	0
G	596	0	0	0	1178	0	111	1283	470	0	0	250	22	123	484	0	0	482	232	45	286	0	0	0	37	0
H	5077	7	0	0	13695	17	0	0	4065	0	0	23	17	24	1879	2	1	319	49	866	286	0	6	0	177	0
I	664	298	1830	1357	1112	714	913	8	8	0	289	1322	1664	9708	1398	242	18	995	3371	4648	22	627	0	82	0	179
J	22	0	0	0	100	0	0	0	0	0	0	0	0	0	84	0	0	0	0	0	250	0	0	0	0	0
K	40	15	2	1	1109	4	4	2	537	0	0	58	2	424	2	3	0	0	133	0	15	0	34	0	26	0
L	1317	13	24	1524	3168	347	7	0	2261	0	118	2430	166	6	1322	64	1	74	423	372	321	91	154	0	1965	0
M	1406	362	1	0	3192	14	0	0	1029	0	0	8	206	28	1237	638	0	69	283	5	363	0	1	0	155	0
N	552	19	967	4295	2957	138	4333	19	993	12	312	354	34	220	2350	14	44	16	1770	3004	236	119	25	7	450	5
O	144	430	505	587	76	3716	231	18	342	4	427	1180	1990	5162	1155	639	0	3831	965	2031	5134	626	1592	47	93	21
P	1228	0	0	0	1682	2	0	177	461	0	0	785	8	17	991	588	0	957	211	340	309	0	3	0	48	0
Q	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	0	409	0	0	0	0	0
R	1596	45	181	736	6480	99	225	146	2109	0	286	347	397	421	2298	93	0	476	1316	1351	537	103	74	1	1067	0
S	1131	8	469	8	2703	41	15	1332	1633	0	113	342	259	98	1380	657	38	3	1386	4134	750	0	150	0	148	0
T	1405	12	147	2	3670	20	1	14399	2808	0	0	520	53	19	4163	11	0	1354	901	737	694	0	348	0	917	0
U	415	267	455	196	390	65	815	0	261	0	0	1647	359	1290	44	600	0	1752	1389	2037	0	15	0	8	12	6
V	299	0	0	0	3138	0	0	0	534	0	0	0	0	1	291	0	0	3	0	0	4	0	0	0	35	0
W	3469	0	0	39	1650	2	0	1947	1995	0	6	57	0	451	1242	0	0	175	169	2	2	0	0	0	6	0
X	81	0	106	0	55	1	0	10	147	0	0	1	0	0	1	113	1	0	0	136	22	0	3	0	16	0
Y	28	20	8	14	536	3	1	5	165	1	0	33	72	10	1346	22	0	34	374	144	0	5	31	0	0	0
Z	36	0	0	0	177	0	0	0	40	0	0	9	0	0	20	0	0	0	0	0	1	2	0	0	5	15

Difference between revisions of "Transitions within words"

Latest revision as of 15:56, 17 August 2009

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@@ Line 1: / Line 1: @@
 The following table is a raw count of transitions (from 1984 by George Orwell) within a single word.  ie. in the phrase "hi there" the pairs counted are 'HI' 'TH' 'HE' 'ER' 'RE' ('IT' is NOT counted as it is not within a single word).
-A transition from 'O' to 'D' is counted in row 'O' and column 'D'. This means that to find the probability of transition to letter 'D' given letter 'T' (ie. the pair 'TD' within a single word) we would find the value in row 'T' column 'D' (2 in this case) and divide it by the sum of the elements in the row 'T' (1405 + 12 + 147 + etcetera)
+A transition from 'O' to 'D' is counted in row 'O' and column 'D'.
+To find the probability of transition to letter 'D' given letter 'T' (ie. the pair 'TD' within a single word) we would find the value in row 'T' column 'D' (2 in this case) and divide it by the sum of the elements in the row 'T' (1405 + 12 + 147 + etcetera)
+However, to find the probability of a certain pair appearing in the text (as opposed to any other pair possibility) then we (once again) find the value in row 'T' column 'D' (for the pair 'TD') and then divide by the sum total of all of the elements in the table (not just in the same row as above).